What is the percentage yield if 14.97 g of ethanol produces 6.38 g of ethene?

To determine the percentage yield of ethene from ethanol, you first need to know the theoretical yield based on the stoichiometry of the reaction. Ethanol (C2H5OH) can be converted to ethene (C2H4) through dehydration, typically using an acid catalyst.

The balanced chemical equation for the dehydration of ethanol to ethene can be represented as:

C2H5OH → C2H4 + H2O

From the equation, you see that 1 mole of ethanol produces 1 mole of ethene.

To find the theoretical yield of ethene, you first convert the mass of ethanol used to moles. The molar mass of ethanol is approximately 46.07 g/mol.

Calculating the moles of ethanol used:

[

\text{Moles of ethanol} = \frac{14.97 , \text{g}}{46.07 , \text{g/mol}} \approx 0.324 , \text{mol}

]

According to the stoichiometry of the reaction, 0.324 moles of ethanol will yield 0.324 moles of ethene. Now, converting the moles of ethene produced